A bar magnet is released from rest coaxially | vedclass

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Question

(B) As the bar magnet falls through the copper tube,the change in magnetic flux linked with the tube induces eddy currents in the copper walls.Accordi

Vedclass · Accepted Answer

Will move with almost constant speed

Vedclass · Answer

(B) As the bar magnet falls through the copper tube,the change in magnetic flux linked with the tube induces eddy currents in the copper walls.According to Lenz's law,these eddy currents create a magnetic field that opposes the motion of the falling magnet.As the magnet gains speed,the induced electromotive force $(EMF)$ and the resulting eddy currents increase,leading to a greater opposing magnetic force.Eventually,the upward magnetic force balances the downward gravitational force $(mg)$.At this point,the net force on the magnet becomes zero,and it reaches a terminal velocity,moving with an almost constant speed.

$A$ bar magnet is released from rest coaxially along the axis of a very long,vertical copper tube. After some time,the magnet:

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